Change response status code without info.context.response
i would like to change a response status code without having to manually use info.context.response
example:
@strawberry.field
def something(some_arg: Optional[str]) -> str:
response: Response = info.context.response
if cond:
response.status_code = 400
raise Exception("...")
if cond:
response.status_code = 401
raise Exception("...")
if cond:
response.status_code = 402
raise Exception("...")
if cond:
response.status_code = 403
raise Exception("...")
return "ok"this gets very repetitive, so i tried doing something like this:
class Error400(Exception):
pass
@strawberry.field
def something() -> str:
if cond:
raise Error400("...")
return "ok"
class Router(GraphQLRouter):
async def process_result(
self, request: Request, result: ExecutionResult
) -> GraphQLHTTPResponse:
...
if Error400 in errors:
response.status_code = 400 # we cant access response from process_resultis it possible to do something like this, or do i have to continue to do it manually?
strawberry-graphql / strawberry
A GraphQL library for Python that leverages type annotations 🍓
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