Description
Use .some() or .every() check on one array repeatly can simplify to use one call.
Fail
if (
array.some(element => element.foo === 1)
|| array.some(element => element.bar === 2)
) {}if (
array.every(element => element.foo === 1)
&& array.every(element => element.bar === 2)
) {}Pass
if (
array.some(element => element.foo === 1 || element.bar === 2)
) {}if (
array.every(element => element.foo === 1 && element.bar === 2)
) {}Proposed rule name
Not sure about the name yet
Additional Info
No response
sindresorhus / eslint-plugin-unicorn
More than 100 powerful ESLint rules
4.2k
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